The demo above shows three waveforms. From top to bottom, they are coloured blue, red and purple, and are mathematically described by the following equations
\[A- y_1 = \sin{(2\pi f_1 t)} \] \[B- y_2 = 1 + A_2\cos{(2\pi f_2 t)} \] \[C- y_{1\times2} = y_1 \times y_2 = \sin{(2\pi f_1 t)}\] \[ \left(1 + A_2\cos{(2\pi f_2 t)}\right) \]
where \( f1 \) and \( f2 \) are the frequencies of each wave, \( A_2 \) is the amplitude of the second wave, and \( t \) is the time. The amplitude of the first wave is 1.
You can check the "Sound on/off" checkbox to hear what \( y_{1\times2} \) sounds like (this feature may not work in older browsers or Internet Explorer). You should be able to hear a note that has a frequency of \( f_1 \), that is going up and down in loudness at a rate of \( f_2 \). For example, if the value of \( f_2 \) is 1Hz, the volume should go to zero once every second.
The \( y_2\) waveform is acting as a modulator and creates an amplitude envelope. This means its magnitude is determining the magnitude of \( y_{1\times2} \). When the value of \( A_2 \) is zero, the modulator has a constant value of 1, and the line \( y_{1\times2} \) is exactly equal to \( y_1 \) meaning you will not hear any variation in loudness.
If you increase \( f_2 \) higher and higher, you may begin to hear two discernible frequencies, and the tone sounds a little like a dial tone. This can be explained by understanding that the trigonometric identity
\[ \sin{\left(\frac{x+y}{2}\right)}\cos{\left(\frac{x-y}{2}\right)} \] \[= \frac{1}{2} \left[\sin{(x)} + \sin{(y)}\right] \]
allows us to write the equation for \( y_{1\times2} \) as a sum of sine waves, which is equivalent to playing two tones of different frequencies. The fact that rapidly modulating the amplitude of one wave results in a waveform identical to playing two notes of different frequencies is quite remarkable and for more information on such wave interference, please see our wave interference and beat frequency demo.
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